I was pleased by the attempts to this puzzle. The tricky part was in fact that you'd expect using integrals (because it's about area) but you actually needed derivates. Sorry for the bad drawing again :joy: .



I was pleased by the attempts to this puzzle. The tricky part was in fact that you'd expect using integrals (because it's about area) but you actually needed derivates. Sorry for the bad drawing again :joy: .
Into Maths Amino? the community.
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Comments (9)
Here is a different approach to this question
Very cool indeed! I'm amazed
There is no need for calculus; at 2sin(2a), it is well known the upper bound of sin2a is 1, so the upper bound of 2sin2a is 2
Oh yeah I just noticed that thank you :wink: